Astromart

Hello Wesley.

Once again, congrats on a fantastic image.

Could I trouble you to post a couple of raw images? I'd be interested what this image looks like prior to stacking/processing.

Derrick.

December 20, 2004 05:18 PM Forum: CCD Imaging and Processing/Solar System

Hi Wes.

I'm using a 19" View Sonic CRT. In my own opinion, I have yet to see an LCD that is as clear and sharp as a CRT. (I stress that this is only my opinion... I don't want to start a CRT vs. LCD war).

Good luck.

Derrick.

January 19, 2005 11:24 PM Forum: Beginning Astronomy?

Image Resolution calculations.

Posted By Derrick Lipinski

Hi Ben.

From a land surveyor's perspective: roughly (very) assuming a distance of 250,000mi to the moon (402,250Km or 402,250,000m) using basic trig for a 3m object at that distance:

[arctan(1.5m/402,250,000m)]*2 would equal resolving power in terms of "arcsec" of 0.00154" (or considering that the difference is negligible in this case: arctan(3m/402,250,000m) would suffice).

That is to say: if you were to be capable of detecting the "speck" on the moon that would be the 3m base of the LEM, you would require a telescope with a resolving power of about 0.00154 arcseconds.

0.68"/0.00154" = 442. You would require a telescope with roughly 442 times the resolving power of what you are currently using to detect a 3m object on the moon (assuming no atmosphere).

Derrick

Image of the day

About Astromart

My Account

Need Help?

Posts Made By: Derrick Lipinski

NGC 7000 One-Shot Color vs. RGB

Lunar Craters with SV-102

N7635 HaRGB 10 hours of Fun

Sunspots 11/26 and 11/27

Saturn 11-27-04

DSI's Blue Snowball, second try...

Saturn 12/03/04

Saturn 12/03/04

Poll - LCD or CRT monitor

Image Resolution calculations.

Funding Member

Sponsors

Search